X0 and the velocity is zero and a is zero& We can agree on that. 保持-3没变,x,remains,minus,three,速度是0,加速度是-,我们同意这一点。
Or we can rewrite this as du dV minus T surroundings dS is less than zero. 或者我们可以写为,加上压强p,du,plus,external,pressure,乘以dV减去环境温度T乘以dS小于零。
1-0 Plus the k component is one minus zero. 加上k分量,也就是。
Mg So the potential energy equals mg times R one minus cosine theta, 0 if I choose zero there. 所以势能等于,乘以,如果我选择那里是。
Let's do a special example where our surface is given by the equation z minus f of x, y equals zero. 来做一个特殊的例子,曲面是由方程z,-,f,等于,0,给出的。
If you take it to go from minus pi to pi, the average theta will be zero. 如果θ取值为-π到π,θ的平均值就是。
SdT This has minus T dS minus S dT, but the dT part is zero because we're at constant temperature. 这一项包含负的Tds和,但是dT的部分等于零,因为温度为常数。
Some lower boundary for interest rates surely exists. But it is minus 1 or minus 2 per cent, not zero. 更低的利率分界线肯定存在,但那是-1%或-2%,而不是零。
1-0 If we compute this, the I component will be one minus zero. 如果计算这个,那么i分量是。
V That, of course, is v2 minus v center of mass, 0 but this was zero. 它是v2减去重心速度,但这是。
We define average velocity as the position at time four seconds minus the position at time zero, 4 divided by four. 我们定义平均速度,是四秒时的位置,减去0秒时的位置,除以。
So now if we just write out a few of the individual terms in the sum, it's one plus e to the minus epsilon zero over kT. 那么现在如果我们只是写出,求和中的一些项,它是一加上e的负ε0除以kT次方。
That says that minus q1 prime plus q1 is greater than zero. 这就是说1,负q1一撇加q1大于零。
Left shoulder and right shoulder freezing-thawing process of rubble slope and gravel pavement embankments bears an analogy to natural ground, but the curve of temperature changing with deepness is minus grads, tending to become zero grads for rubble slope and gravel pavement refrigeration effect. 碎石护坡和片石护道路基左右路肩冻融过程与天然场地类似,但地温随深度变化曲线为负梯度型,在碎石护坡和片石护道冷却作用下,有向零梯度型变化的趋势。